Hi

I did check. It looks correct according to the book.

What is your doubt ?

1. Question does not state the figure to be a parallelogram or sets of two parallel lines.
2. The diagonals given in the figure are AD and BC instead of AC and BD, in which case Option C may be considered.

We do not have the caption "the diagram could not drawn the scale"

Therefore , with the caption, it could be a rectangle, rhombus, anything

But we do not have. So it is a parallelogram according to what is before our eyes

Hope this hleps

Thanks Carcass for the response. Kudos!

But by GRE rules for QC questions, we cannot assume anything, even the nonstated. It's like those question where you have a circle, and a point that seems to be the center, but there is no caption that says that such point is the center, but that doesn't mean you can safely assume the point is indeed the center. I think this kind of trick is not that valid. Even at the beginning of the Quant section you have the rules.

yes that is also true. I agree.

However, if nothing is stated we can reasonably infer that the figure in front of us is a parallelogram as it is rather than a rectangular shape.

regards

Could this shape be a rhombus?

yes sir. could also be

That means the shape is any type of parallelogram, square, rectangle, rhombus etc but the question is, do all parallelograms have equal diagonals?

The question is a bit misleading.

It could be also a kite

However, regardless that, If I were in front of this question my first thought was

If we move the vertexes around - Point A - to have a rhombus, a parallelogram, a rectangle, a kite....moving A left to the right and vice-versa then those segments are still the same length because E is at the intersection.

That's my reasoning. Of course, I could be wrong

We dont even know whether the sides are parallel, I would have chosen D for this question

deal with