GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
If A is 25 kilometers east of N. which is 12 kilometers sout
[#permalink]
03 May 2017, 02:47
03 May 2017, 02:47
1
Expert Reply
1
Bookmarks
00:00
Question Stats:
79% (01:44) correct
20% (02:06) wrong based on 128 sessions
Hide Show timer Statistics
If A is 25 kilometers east of B, which is 12 kilometers south of C, which is 9 kilometers west of D, how far is it. in kilometers. from A to D?
A) \(20\)
B)\(5\sqrt{34}\)
C) \(5\sqrt{41}\)
D) \(10 \sqrt{13}\)
E) \(71\)
Re: If A is 25 kilometers east of N. which is 12 kilometers sout
[#permalink]
22 Sep 2017, 07:05
22 Sep 2017, 07:05
1
Given the instructions, the figure is a trapezoid with larger base 25km long, smaller base 17km long and height 12km long. We are asked to find the oblique side. In order to find it we can exploit the fact that drawing the height DH we get a triangle whose hypotenuse is AD. Thus, using Pitagora's theorem we get \(sqrt(12^2+18^2)\) that is not equal to 20.
In order to be 20 the number under the square root should be 400. Thus, CD must be equal to 9 so that AH is equal to 16.
Is there a typo or am I wrong in my computations?
In order to be 20 the number under the square root should be 400. Thus, CD must be equal to 9 so that AH is equal to 16.
Is there a typo or am I wrong in my computations?
Re: If A is 25 kilometers east of N. which is 12 kilometers sout
[#permalink]
22 Sep 2017, 07:36
22 Sep 2017, 07:36
1
IlCreatore wrote:
Given the instructions, the figure is a trapezoid with larger base 25km long, smaller base 17km long and height 12km long. We are asked to find the oblique side. In order to find it we can exploit the fact that drawing the height DH we get a triangle whose hypotenuse is AD. Thus, using Pitagora's theorem we get \(sqrt(12^2+18^2)\) that is not equal to 20.
In order to be 20 the number under the square root should be 400. Thus, CD must be equal to 9 so that AH is equal to 16.
Is there a typo or am I wrong in my computations?
In order to be 20 the number under the square root should be 400. Thus, CD must be equal to 9 so that AH is equal to 16.
Is there a typo or am I wrong in my computations?
Your reasoning is correct, even I landed up with the same solution.
