Re: In a queue at a Mall, Pat is standing three positions behind Mike who
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31 Mar 2025, 04:00
If Pat is standing two persons behind Mike, who is standing $\(5^{\text {th \)$ from the counter, the position of Pat from the counter is $\((5+3)=8\)$ th. So, Pat is standing seven persons behind from the counter.
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Now as there 12 persons in queue, Pat must have $\((12-8)=4\)$ persons behind him i.e. Pat is 4 persons ahead from the end.
So Pat's position in queue from the end is $\((4+1)=5\)$ th .
Next as Mike is $\(5^{\text {th \)$ from the counter, he must have $\((12-5)=7\)$ persons behind him, so his position from the end is $\((7+1)=8\)$ th
Hence options (A) \& (C) are correct. .