GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 17Live Online Classes with Top GRE Expert Rich Zwelling
08:00 PM EST
-10:00 PM EST
Get live instruction from a top-scoring, industry-recognized GRE teachers + 6 months of access to TTP Self-Study included! Tues/Thur Sept 7, 2026---Feb. 2, 2027, 1:00pm-3:00pm EST
Dec 14Live Online Classes with Top GRE Expert Michael Butville
08:00 PM EST
-10:00 PM EST
Get live instruction from a top-scoring, industry-recognized GRE teachers + 6 months of access to TTP Self-Study included! Mon/Wed Dec. 14, 2026---Feb. 22, 2027, 8:00pm-10:00pm EST
Janine travelled 1,320 miles on her road trip at an average
[#permalink]
Updated on: 01 Oct 2017, 20:32
Updated on: 01 Oct 2017, 20:32
4
8
Bookmarks
00:00
Question Stats:
26% (01:11) correct
73% (01:42) wrong based on 84 sessions
Hide Show timer Statistics
Janine travelled 1,320 miles on her road trip at an average speed of 45 miles per hour.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The length of time, in hours, Janine spent driving |
The length of time, in minutes, Janine spent driving to cover the first 2% of her total travel distance |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: Janine travelled 1,320 miles on her road trip at an average
[#permalink]
01 Oct 2017, 05:45
01 Oct 2017, 05:45
3
Expert Reply
Total distance = 1320 miles.
Average speed is = 45 miles/hour.
Time taken for travel = \(\frac{1320}{45}=29.3333\)hours. (Quantity A)
2% of total distance = \(\frac{2}{100} \times 1320\) miles = 26.4 miles.
Time taken to travel this @ average speed = \(\frac{26.4}{45}=0.58666666666\)hours or 35.2 minutes. (Quantity B)
So numerical value of Quantity B is greater!
Average speed is = 45 miles/hour.
Time taken for travel = \(\frac{1320}{45}=29.3333\)hours. (Quantity A)
2% of total distance = \(\frac{2}{100} \times 1320\) miles = 26.4 miles.
Time taken to travel this @ average speed = \(\frac{26.4}{45}=0.58666666666\)hours or 35.2 minutes. (Quantity B)
So numerical value of Quantity B is greater!
Re: Janine travelled 1,320 miles on her road trip at an average
[#permalink]
01 Oct 2017, 20:42
01 Oct 2017, 20:42
2
sandy wrote:
Total distance = 1320 miles.
Average speed is = 45 miles/hour.
Time taken for travel = \(\frac{1320}{45}=29.3333\)hours. (Quantity A)
2% of total distance = \(\frac{2}{100} \times 1320\) miles = 26.4 miles.
Time taken to travel this @ average speed = \(\frac{26.4}{45}=0.58666666666\)hours or 35.2 minutes. (Quantity B)
So numerical value of Quantity B is greater!
Average speed is = 45 miles/hour.
Time taken for travel = \(\frac{1320}{45}=29.3333\)hours. (Quantity A)
2% of total distance = \(\frac{2}{100} \times 1320\) miles = 26.4 miles.
Time taken to travel this @ average speed = \(\frac{26.4}{45}=0.58666666666\)hours or 35.2 minutes. (Quantity B)
So numerical value of Quantity B is greater!
This is not the right answer,
The option indeed is D.
Since her average speed is given and we do not know what is her actual speed at first 2% of trip so it could be any value for example, she might have driven 60 miles per hour for the first hour and then later traveled slower than 45 miles per hour (suppose 30 m/hr)for a period of time. Because it is not known how much Janine’s speed varied on the trip, the relationship cannot be determined from the information given.
