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Four pipes A, B, C, and D can fill a tank in 3, 6, 9 and 12 days respe
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06 Apr 2025, 00:42
06 Apr 2025, 00:42
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60% (01:43) correct
40% (02:03) wrong based on 5 sessions
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Four pipes A, B, C, and D can fill a tank in 3, 6, 9 and 12 days respectively. What is the least portion of tank that can be filled in one day by any three of the pipes working together at their respective rates?
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13/36
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Re: Four pipes A, B, C, and D can fill a tank in 3, 6, 9 and 12 days respe
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10 Apr 2025, 04:45
10 Apr 2025, 04:45
Expert Reply
Since we need to consider the least portion of the tank to be filled by any of the three pipes, we will consider the three pipes $B, C$, and $D$, which are less efficient in filling.
Therefore, the least portion that can be filled by these three pipes in one day is $\(\frac{1}{6}+\frac{1}{9}+\frac{1}{12}=\frac{6+4+3}{36}=\frac{13}{36}\)$. Thus, the correct answer is $\(\frac{13}{36}\)$.
Therefore, the least portion that can be filled by these three pipes in one day is $\(\frac{1}{6}+\frac{1}{9}+\frac{1}{12}=\frac{6+4+3}{36}=\frac{13}{36}\)$. Thus, the correct answer is $\(\frac{13}{36}\)$.
gmatclubot
Re: Four pipes A, B, C, and D can fill a tank in 3, 6, 9 and 12 days respe [#permalink]
10 Apr 2025, 04:45
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