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If $x$ and $y$ are two numbers on the number line and $y^2$ $<100$ and
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25 Apr 2025, 02:07
25 Apr 2025, 02:07
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21% (02:49) correct
78% (02:19) wrong based on 42 sessions
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If $\(x\)$ and $y$ are two numbers on the number line and $\(y^2<100\)$ and $\(-\)\(\frac{1}{3}<x<\frac{2}{3}\)$ then, which of the following must be true?
(A) $\(x y<6\)$
(B) $\(y-x<10\)$
(C) $\(-11<y-x<11\)$
(D) $\(x+y<10.3\)$
(E) $\(\frac{-28}{3}<x+y<\frac{21}{3}\)$
(A) $\(x y<6\)$
(B) $\(y-x<10\)$
(C) $\(-11<y-x<11\)$
(D) $\(x+y<10.3\)$
(E) $\(\frac{-28}{3}<x+y<\frac{21}{3}\)$
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Re: If $x$ and $y$ are two numbers on the number line and $y^2$ $<100$ and
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30 Apr 2025, 00:34
30 Apr 2025, 00:34
1
-10 < y < 10 and -1/3 < x < 2/3
Gives -31/3 < x + y < 32/3
Answer choice E is always within this range, why is the answer C
Gives -31/3 < x + y < 32/3
Answer choice E is always within this range, why is the answer C
Re: If $x$ and $y$ are two numbers on the number line and $y^2$ $<100$ and
[#permalink]
09 Aug 2025, 17:16
09 Aug 2025, 17:16
1
