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What is the average (arithmetic mean) number of parking tickets issue
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27 Jul 2025, 10:22
27 Jul 2025, 10:22
Expert Reply
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Question Stats:
0% (00:00) correct
100% (02:27) wrong based on 2 sessions
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Attachment:
GRE What is the average (arithmetic mean) number.png [ 226.6 KiB | Viewed 229 times ]
What is the average (arithmetic mean) number of parking tickets issued to the drivers who were issued 6 or more tickets?
A. 7.0
B. 7.5
C. 8.0
D. 8.5
E. 9.0
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Re: What is the average (arithmetic mean) number of parking tickets issue
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14 Aug 2025, 10:18
14 Aug 2025, 10:18
Expert Reply
If the total number of tickets is 420 (from the chart's note), and we know tickets distributed by group counts, maybe we can estimate this:
Number of drivers in each category:
GRE If the total number of tickets is 420.png [ 23.89 KiB | Viewed 11 times ]
Calculate total tickets issued to the first five groups:
- 1 ticket $* 52$ drivers $=52$
- 2 tickets * 35 drivers = 70
- 3 tickets * 40 drivers = 120
- 4 tickets * 22 drivers $=88$
- 5 tickets * 6 drivers $=30$
Sum for these groups $\(=52+70+120+88+30=360\)$ tickets
Total tickets = 420
Tickets issued to "6 or more" drivers $\(=420-360=60\)$ tickets
Number of drivers in this group $=8$
Average tickets per driver in the "6 or more" group:
$$
\(\frac{60}{8}=7.5\)
$$
Final answer:
B. 7.5
Number of drivers in each category:
Attachment:
GRE If the total number of tickets is 420.png [ 23.89 KiB | Viewed 11 times ]
Calculate total tickets issued to the first five groups:
- 1 ticket $* 52$ drivers $=52$
- 2 tickets * 35 drivers = 70
- 3 tickets * 40 drivers = 120
- 4 tickets * 22 drivers $=88$
- 5 tickets * 6 drivers $=30$
Sum for these groups $\(=52+70+120+88+30=360\)$ tickets
Total tickets = 420
Tickets issued to "6 or more" drivers $\(=420-360=60\)$ tickets
Number of drivers in this group $=8$
Average tickets per driver in the "6 or more" group:
$$
\(\frac{60}{8}=7.5\)
$$
Final answer:
B. 7.5
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