Last visit was: 19 Sep 2025, 03:54 It is currently 19 Sep 2025, 03:54

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
Verbal Expert
Joined: 18 Apr 2015
Posts: 33402
Own Kudos [?]: 39808 [5]
Given Kudos: 26537
Send PM
Most Helpful Community Reply
avatar
Manager
Manager
Joined: 22 Jan 2020
Posts: 120
Own Kudos [?]: 251 [6]
Given Kudos: 10
Send PM
General Discussion
avatar
Manager
Manager
Joined: 19 Jan 2020
Posts: 56
Own Kudos [?]: 70 [0]
Given Kudos: 0
Send PM
User avatar
Senior Manager
Senior Manager
Joined: 10 Feb 2020
Posts: 496
Own Kudos [?]: 363 [0]
Given Kudos: 299
Send PM
Re: The U.S. Weather Bureau has provided the following informati [#permalink]
Any other explanation?
Manager
Manager
Joined: 23 May 2021
Posts: 146
Own Kudos [?]: 47 [0]
Given Kudos: 23
Send PM
Re: The U.S. Weather Bureau has provided the following informati [#permalink]
Isnt the median here , the median of two numbers? Or am i wrong?
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Own Kudos [?]: 3535 [1]
Given Kudos: 172
Location: India
WE:Education (Education)
Send PM
Re: The U.S. Weather Bureau has provided the following informati [#permalink]
1
Explanation:

To find the mean, let us first arrange these 20 terms in ascending order:
464, 505, 564, 585, 604, 608, 616, 653, 657, 660, 697, 704, 741, 856, 888, 906, 918, 926, 947, 1102

Median (for even number of terms) = \(\frac{10^{th} term + 11^{th} term}{2} = \frac{660 + 697}{2} = 678.5\)

Average (given) = 730
SD (given) = 168
1SD of mean means 1SD above or 1SD below mean i.e. (730 - 168) to (730 + 168) = 562 to 898

Find the numbers which are less than the median;
464, 505, 564, 585, 604, 608, 616, 653, 657, 660

Which are not within one standard deviation of the mean;
464, 505, 564, 585, 604, 608, 616, 653, 657, 660

Required probability = \(\frac{2}{20} (100) = 10\)%
Hence, option A
avatar
Intern
Intern
Joined: 17 Sep 2025
Posts: 1
Own Kudos [?]: 1 [1]
Given Kudos: 0
Send PM
Re: The U.S. Weather Bureau has provided the following informati [#permalink]
1
There are several ways to go about this problem, but the objective is to chose the path that will take the least amount of time. Hence, usually you would and certainly can arrange all the numbers from least to greatest to find the median, but I personally believe that this may take too long.

Thus, after reading the problem, the first I did was count how many numbers were given; I counted 10 in the top row, and hence, automatically knew there were a total of 20 because of the alignment with the second row.

Next, if you know the formula for calculating the median, it will make your life much simpler...

There are two formulas used to calculate the median, based upon the number of observations you are given in your data set.

For an odd number of observations (n): (n+1) / 2

For an even numbers of observations (n): [(n / 2) + (n+1) / 2] / 2

In our problem, we have noted that there are 20 numbers, aka 20 observations in our data set.

So, first find which 2 terms you will be using to find their average:

(20 / 2) + (20 + 1) / 2 = 10th term + 11th term

Start crossing out the numbers, starting with 464, until finding your 10th and 11th terms.

10th term = 660
11th term = 697

Average these two numbers, and you get 678.5.

Now, we can start eliminating numbers according to the last sentence of information we are given.

Primarily, we are looking for numbers that are not within 1 standard deviation of the mean.

730 - 168 = 562

So, we are looking for numbers below 562 that are also less than the median, 678.5.

Now, notice that the numbers we have already crossed out are where we are going to find our numbers that fit the criteria.

Finally, we find that the only two numbers that fit this criteria are 464 and 505.

Hence, (2 / 20) x 100% = 10%

And voila, we get our answer!
Prep Club for GRE Bot
Re: The U.S. Weather Bureau has provided the following informati [#permalink]
Moderators:
GRE Instructor
125 posts
GRE Forum Moderator
37 posts
Moderator
1141 posts
GRE Instructor
234 posts
Moderator
37 posts
GRE Forum Moderator
113 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne