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Which is greater x/y or y/x
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Updated on: 22 Jul 2019, 02:27
Updated on: 22 Jul 2019, 02:27
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67% (01:27) correct
32% (00:50) wrong based on 52 sessions
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\(|x| \geq 1\)
\(|y| < \frac{1}{2}\)
\(x \neq 0\) and \(y \neq 0\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
\(|y| < \frac{1}{2}\)
\(x \neq 0\) and \(y \neq 0\)
Quantity A |
Quantity B |
\(\frac{x}{y}\) |
\(\frac{y}{x}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Originally posted by anuppatel012 on 20 Jul 2019, 22:07.
Last edited by Carcass on 22 Jul 2019, 02:27, edited 2 times in total.
Last edited by Carcass on 22 Jul 2019, 02:27, edited 2 times in total.
Edited by Carcass
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Which is greater x/y or y/x
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21 Jul 2019, 04:43
21 Jul 2019, 04:43
1
anuppatel012 wrote:
\(|x| \geq 1\)
\(|y| < \frac{1}{2}\)
\(x \neq 0\) and \(y \neq 0\)
\(|y| < \frac{1}{2}\)
\(x \neq 0\) and \(y \neq 0\)
Quantity A |
Quantity B |
\(\frac{x}{y}\) |
\(\frac{y}{x}\) |
Let's test some possible values of x and y
case i: Since \(|x| \geq 1\) and \(|y| < \frac{1}{2}\), one possible pair of values is \(x=1\) and \(y=\frac{1}{3}\)
We get
Quantity A: \(\frac{1}{\frac{1}{3}}=3\)
Quantity B: \(\frac{\frac{1}{3}}{1}=\frac{1}{3}\)
In this case, Quantity A is greater
case ii: Another possible pair of values is \(x=-1\) and \(y=\frac{1}{3}\)
We get
Quantity A: \(\frac{-1}{\frac{1}{3}}=-3\)
Quantity B: \(\frac{\frac{1}{3}}{-1}=\frac{-1}{3}\)
In this case, Quantity B is greater
Answer: D
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Re: Which is greater x/y or y/x
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21 Jul 2019, 04:48
21 Jul 2019, 04:48
Hi, is it possible to solve this using algebraic approach first and then substitute the values of x and y ?
