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A drawer contains 6 socks. Two socks are randomly selected without rep

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A drawer contains 6 socks. Two socks are randomly selected without rep [#permalink] New post   19 Apr 2022, 01:47
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A drawer contains 6 socks. Two socks are randomly selected without replacement. The probability is greater than 0.4 that both socks will be white.

Quantity A
Quantity B
The probability that both socks will be black
1/6



A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
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B
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Re: A drawer contains 6 socks. Two socks are randomly selected without rep [#permalink] New post   05 May 2022, 22:36
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Re: A drawer contains 6 socks. Two socks are randomly selected without rep [#permalink] New post   21 May 2022, 13:15
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Total: 6 socks.
Get 2 white socks probability without replacement: [(x)/6]*[(x-1)/5]=0.4
Equation: x^2-x-12=0
(x-4)(x+3)=0
x must be positive so the answer it 4.

So there are 4 white socks and another 2 socks (assuming black, not mentioned in the question, so if not black, the answer will be D).
If there are 4 white and 2 black socks. The probability to get 2 black socks is: (1/6)*(1/5) = 1/30.

The answer is B.
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Re: A drawer contains 6 socks. Two socks are randomly selected without rep [#permalink] New post   23 May 2022, 03:48
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Paul121 wrote:
Total: 6 socks.
Get 2 white socks probability without replacement: [(x)/6]*[(x-1)/5]=0.4
Equation: x^2-x-12=0
(x-4)(x+3)=0
x must be positive so the answer it 4.

So there are 4 white socks and another 2 socks (assuming black, not mentioned in the question, so if not black, the answer will be D).
If there are 4 white and 2 black socks. The probability to get 2 black socks is: (1/6)*(1/5) = 1/30.

The answer is B.


Not really.
Your very first expression should have " > 0.4 " and not " = 0.4"
which will yield (x-4)(x+3) > 0
and, x>4

x = {5,6}

Since white balls are either 5 or 6 in numbers, black balls are 0 or 1 in number.
So, the probability of getting 2 black balls is 0.

Hence, B is the answer.
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Re: A drawer contains 6 socks. Two socks are randomly selected without rep [#permalink] New post   07 Jul 2022, 00:03
Paul121 wrote:
Total: 6 socks.
Get 2 white socks probability without replacement: [(x)/6]*[(x-1)/5]=0.4
Equation: x^2-x-12=0
(x-4)(x+3)=0
x must be positive so the answer it 4.

So there are 4 white socks and another 2 socks (assuming black, not mentioned in the question, so if not black, the answer will be D).
If there are 4 white and 2 black socks. The probability to get 2 black socks is: (1/6)*(1/5) = 1/30.

The answer is B.


What about 30 in the denominator in the first equation? Can you expand on the first equation?
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Re: A drawer contains 6 socks. Two socks are randomly selected without rep [#permalink] New post   11 Oct 2025, 11:09
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Re: A drawer contains 6 socks. Two socks are randomly selected without rep [#permalink]
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