GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
x2 – 2xy + y2 = 0 and y =
[#permalink]
15 Apr 2018, 04:45
15 Apr 2018, 04:45
1
Expert Reply
6
Bookmarks
00:00
Question Stats:
61% (01:30) correct
38% (01:50) wrong based on 63 sessions
Hide Show timer Statistics
\(x^2 - 2xy + y^2 = 0\) and \(y =\frac{9}{x}\)
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(y\) |
\(3\) |
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
Drill 1
Question: 10
Page: 512
Question: 10
Page: 512
Re: x2 – 2xy + y2 = 0 and y =
[#permalink]
22 Apr 2018, 12:25
22 Apr 2018, 12:25
2
Expert Reply
Explanation
Factor the quadratic expression to get \((x - y)(x - y) = 0\); \(x - y\) must equal 0, so you know that x = y.
Thus, \(y=\frac{9}{y}\) , \(y^2 = 9\), and \(y = 3\) — eliminate choices (A) and (B)—or –3—eliminate choice (C). The answer is choice (D).
Factor the quadratic expression to get \((x - y)(x - y) = 0\); \(x - y\) must equal 0, so you know that x = y.
Thus, \(y=\frac{9}{y}\) , \(y^2 = 9\), and \(y = 3\) — eliminate choices (A) and (B)—or –3—eliminate choice (C). The answer is choice (D).
Re: x2 2xy + y2 = 0 and y =
[#permalink]
13 Oct 2025, 21:41
13 Oct 2025, 21:41
Hello from the GRE Prep Club BumpBot!
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
