The area of a circle is given by $\pi r^2$. If the area of the inner circle is $\(4 \pi\)$, then $\(r^2=4\)$ and $\(r =2\)$. This means, in keeping with the ratio we are given, that the width of the second ring is 2 as well, and that the width of the outer ring is 3 . To find the area of the shaded region, we subtract the area of the white area from the area of the entire figure. The radius of the entire figure is:

$$
\(2+2+3=7\)
$$


The radius of the white concentric circles is:

$$
\(2+2=4\)
$$


Therefore the area of the shaded area is

$$
\((7)^2 \pi-(4)^2 \pi=49 \pi-16 \pi=33 \pi\)
$$


This works out to approximately 104.