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If A, B, and C represent different digits in the multiplication
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02 Nov 2025, 17:43
02 Nov 2025, 17:43
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Question Stats:
22% (02:44) correct
77% (00:46) wrong based on 9 sessions
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If \(A\), \(B\) and \(C\) represent different digits in the multiplication, then $\(\mathrm{A}+\mathrm{B}+\mathrm{C}=\)$
\(\begin{array}{r}
A A B \\
\times \quad B \\
\hline C B 5 B
\end{array}\)
A. 9
B. 12
C. 14
D. 15
E. 17
\(\begin{array}{r}
A A B \\
\times \quad B \\
\hline C B 5 B
\end{array}\)
A. 9
B. 12
C. 14
D. 15
E. 17
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Re: If A, B, and C represent different digits in the multiplication
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Updated on: 03 Nov 2025, 10:54
Updated on: 03 Nov 2025, 10:54
1
15??
-----
here the correction Carcass
i thought the 5 in CB5B was a typing mistake.
ans is 17...
A = 7
B = 6
C = 4
-----
here the correction Carcass
i thought the 5 in CB5B was a typing mistake.
ans is 17...
A = 7
B = 6
C = 4
Originally posted by Syntaxnomad on 03 Nov 2025, 04:47.
Last edited by Syntaxnomad on 03 Nov 2025, 10:54, edited 1 time in total.
Last edited by Syntaxnomad on 03 Nov 2025, 10:54, edited 1 time in total.
Re: If A, B, and C represent different digits in the multiplication
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03 Nov 2025, 06:05
03 Nov 2025, 06:05
1
Expert Reply
nope
