Essentially the question is asking you: where is located the median INSIDE a range of a number ? minimum and maximum numvers ? the lowest and the greatest?

Our range of numbers is represented by the second column

There is our median

To find the range of the median number of hours of TV watched, we first need to determine the total number of students surveyed.
1. Calculate Total Enrollment

We sum the number of students in each range (bin) of the histogram:




The total number of students $(N)$ is 86 .
2. Locate the Median Position

The median is the middle value when the data is ordered. For an even number of data points ( $N=86$ ), the median lies between the $\(\frac{N}{2}\)$th alue and the $\((\frac{N}{2} + 1)\)$th value.

- $\(\frac{86}{2}=43\)$

- $\(\frac{86}{2}+1=44\)$

The median is the average of the $\(\mathbf{4 3}^{\text {rd }}\)$ and $\(\mathbf{4 4}^{\text {th }}\)$ values. Since the median will fall within a specific range (bin), we can determine the range by finding where the $\(43^{\text {rd }}\)$ and $\(44^{\text {th }}\)$ values are located using the cumulative frequency.

3. Determine the Median Range

We find the cumulative count:
- Range 1-5: Students 1 through 13. (Count: 13 )
- Range 6-10: Students 14 through $\(13+35=\mathbf{4 8}\)$.

Since the $\(\mathbf{4 3}^{\text {rd }}\)$ and $\(\mathbf{4 4}^{\text {th }}\)$ students both fall within the $\(\mathbf{6 - 1 0}\)$ hour range, the median number of hours of TV watched must be within this range.

The correct range for the median is B. 6-10.