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In the coordinate plane, rectangle WXYZ has vertices at (–2
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24 May 2017, 01:47
24 May 2017, 01:47
2
Expert Reply
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Question Stats:
89% (02:03) correct
10% (02:09) wrong based on 146 sessions
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In the coordinate plane, rectangle WXYZ has vertices at (–2, –1), (–2, y), (4, y), and (4, –1). If the area of WXYZ is 18, what is the length of its diagonal?
A) \(3 \sqrt{2}\)
B) \(3 \sqrt{3}\)
C) \(3 \sqrt{5}\)
D) \(3 \sqrt{6}\)
E) \(3 \sqrt{7}\)
Re: In the coordinate plane, rectangle WXYZ has vertices at (–2
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10 Oct 2017, 09:15
10 Oct 2017, 09:15
3
Since we have two points as (-1, -2) and (-1, 4) who are in line, we easily compute the length of one of the sides of the rectangle as 4-(-2) = 6.
Then, given the area, we can compute the other side of the rectangle as 18/6 = 3.
Know, the diagonal of the rectangle is the hypotenuse of the right triangle of legs 3 and 6, thus it can be computed as 6^2+3^9 = 45 = 3sqrt(5).
Answer C
Then, given the area, we can compute the other side of the rectangle as 18/6 = 3.
Know, the diagonal of the rectangle is the hypotenuse of the right triangle of legs 3 and 6, thus it can be computed as 6^2+3^9 = 45 = 3sqrt(5).
Answer C
Re: In the coordinate plane, rectangle WXYZ has vertices at (–2
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02 Nov 2018, 12:42
02 Nov 2018, 12:42
Answer should be root(40) i.e. 2 * root(10)
