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xy ≠ 0
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24 May 2017, 01:24
24 May 2017, 01:24
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Question Stats:
30% (01:07) correct
69% (00:55) wrong based on 167 sessions
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\(xy ≠ 0\)
\(\frac{a}{xs}\)\(=632\) and \(\frac{a}{ys}\)\(=158\)
Quantity A |
Quantity B |
x |
y |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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xy ≠ 0
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01 Jul 2021, 06:34
01 Jul 2021, 06:34
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Carcass wrote:
\(xy ≠ 0\)
\(\frac{a}{xs}\)\(=632\) and \(\frac{a}{ys}\)\(=158\)
Quantity A |
Quantity B |
x |
y |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Let's solve each given equation for \(a\)
Take: \(\frac{a}{xs}\)\(=632\)
Multiply both sides of the equation by \(xs\) to get: \(a=632xs\)
Take: \(\frac{a}{ys}\)\(=158\)
Multiply both sides of the equation by \(ys\) to get: \(a=158ys\)
Since both equations are set equal to \(a\), we can write: \(632xs=158ys\)
Divide both sides of the equation by \(s\) to get: \(632x=158y\)
Divide both sides of the equation by \(158\) to get: \(4x=y\)
Now we can replace y with 4x in Quantity B to get :
Quantity A: \(x\)
Quantity B: \(4x\)
At this point we can see that, if x = 1, then Quantity B is greater
Conversely, if x = -1, then Quantity A is greater
Answer: D
General Discussion
Re: xy ≠ 0
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10 Oct 2017, 08:48
10 Oct 2017, 08:48
We can derive the expression of x and y from the information we have and we get \(x = \frac{a}{632*s}\) and \(y = \frac{a}{158*s}\). Then, I would simplify the two expressions multiplying by s/a to get \(x = \frac{1}{632}\) and \(y = \frac{1}{158}\) and I would say B is greater. However the answer is D. How is it possible?
