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Series F is defined as F n = F (n – 1) + 3 and F 1 = 10.
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05 Jun 2017, 07:40
05 Jun 2017, 07:40
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Question Stats:
57% (02:06) correct
42% (01:40) wrong based on 297 sessions
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Series F is defined as F n = F(n – 1) + 3 and F 1 = 10.
Quantity A |
Quantity B |
The sum of F 4 through F 10 |
The sum of F 6 through F 11 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: Series F is defined as F n = F (n – 1) + 3 and F 1 = 10.
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11 Oct 2017, 05:53
11 Oct 2017, 05:53
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The sequence is an arithmetic progression where each term is the precedent plus 3.
Moreover, one can notice that the two columns have many elements in common, since
QA: F4+F5+F6+F7+F8+F9+F10
QB: F6+F7+F8+F9+F10+F11
Thus, we can simplify the comparison to
QA: F4+F5
QB: F11
Now, since each term is three away from the preceding one, we can compute our three terms: F4= F1+3*3 = 19; F5 = F4+3 = 21 and F11 = F5 + 6*3 = 39.
Now QA = 19+21 = 40 and QB = 39.
Quantity A is greater!
Moreover, one can notice that the two columns have many elements in common, since
QA: F4+F5+F6+F7+F8+F9+F10
QB: F6+F7+F8+F9+F10+F11
Thus, we can simplify the comparison to
QA: F4+F5
QB: F11
Now, since each term is three away from the preceding one, we can compute our three terms: F4= F1+3*3 = 19; F5 = F4+3 = 21 and F11 = F5 + 6*3 = 39.
Now QA = 19+21 = 40 and QB = 39.
Quantity A is greater!
General Discussion
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Re: Series F is defined as F n = F (n – 1) + 3 and F 1 = 10.
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27 May 2021, 08:17
27 May 2021, 08:17
IlCreatore wrote:
The sequence is an arithmetic progression where each term is the precedent plus 3.
Moreover, one can notice that the two columns have many elements in common, since
QA: F4+F5+F6+F7+F8+F9+F10
QB: F6+F7+F8+F9+F10+F11
Thus, we can simplify the comparison to
QA: F4+F5
QB: F11
Now, since each term is three away from the preceding one, we can compute our three terms: F4= F1+3*3 = 19; F5 = F4+3 = 21 and F11 = F5 + 6*3 = 39.
Now QA = 19+21 = 40 and QB = 39.
Quantity A is greater!
Moreover, one can notice that the two columns have many elements in common, since
QA: F4+F5+F6+F7+F8+F9+F10
QB: F6+F7+F8+F9+F10+F11
Thus, we can simplify the comparison to
QA: F4+F5
QB: F11
Now, since each term is three away from the preceding one, we can compute our three terms: F4= F1+3*3 = 19; F5 = F4+3 = 21 and F11 = F5 + 6*3 = 39.
Now QA = 19+21 = 40 and QB = 39.
Quantity A is greater!
Best approach!
