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If a = (0.404)^3 ,
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21 Jun 2017, 02:34
21 Jun 2017, 02:34
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If \(a = (0.404)^3\) , b = cube root of 0.404, and c = 0.404, then which of the following is true?
A) a > b > c
B) b > a > c
C) a > c > b
D) c > a > b
E) b > c > a
Re: If a = (0.404)^3 ,
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12 Oct 2017, 00:32
12 Oct 2017, 00:32
Since 0.404 is a number between 0 and 1, when it is elevated to a power greater than 1 the number becomes smaller, while when it is elevated to an improper fraction, i.e. a number between 0 and 1, the number becomes greater.
Given those rules, \(0.404^{\frac{1}{3}}>0.404>0.404^3\)
Answer E
Given those rules, \(0.404^{\frac{1}{3}}>0.404>0.404^3\)
Answer E
Re: If a = (0.404)^3 ,
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26 Jun 2023, 03:44
26 Jun 2023, 03:44
Knowing that:
For any number x that is 0<x<1
\(x^{1/2}>x>x^2\)
We can easily ascertain that b will be the largest, followed by c and lastly a.
E.
For any number x that is 0<x<1
\(x^{1/2}>x>x^2\)
We can easily ascertain that b will be the largest, followed by c and lastly a.
E.
