GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
In the final months of 2008, the state legislature of a certain state
[#permalink]
09 Jan 2026, 10:55
09 Jan 2026, 10:55
Expert Reply
00:00
Question Stats:
0% (00:00) correct
0% (00:00) wrong based on 0 sessions
Hide Show timer Statistics
In the final months of 2008, the state legislature of a certain state announced the availability of a new special statewide Crime Initiative, designed to fight violent crimes in the state. Towns and cities throughout the state could decide to invest in this new crime initiative in 2009, at any level up to $70,000. The graph below shows, for 17 similarly sized towns throughout the state, the money they invested in the Crime Initiative in 2009, and the number of violent crimes that year in that town. A trend line is already displayed on the graph.
GRE In the final months of 2008, the state legislature.png [ 397.28 KiB | Viewed 241 times ]
Among these 17 towns, the median amount invested in the statewide Crime Initiative is
◯ $37,000
◯ $42,000
◯ $53,000
◯ $62,000
◯ $90,000
Attachment:
GRE In the final months of 2008, the state legislature.png [ 397.28 KiB | Viewed 241 times ]
Among these 17 towns, the median amount invested in the statewide Crime Initiative is
◯ $37,000
◯ $42,000
◯ $53,000
◯ $62,000
◯ $90,000
- Part of the project: GRE Daily Quant Challenge - Topic-Wise 2025!!!
- Also replying to the unanswered questions
In the final months of 2008, the state legislature of a certain state
[#permalink]
31 Jan 2026, 12:54
31 Jan 2026, 12:54
Expert Reply
To find the median investment for the 17 towns shown in the scatter plot, you must identify the middle value (the 9th point) when the data is ordered along the horizontal axis ( $x$-axis), which represents the money invested.
1. Identify the Median Position
Since there are $\(\mathbf{1 7}\)$ towns in total, the median is the value in the middle position:
$$
\(\text { Median Position }=\frac{n+1}{2}=\frac{17+1}{2}=9 \text { th town }\)
$$
2. Count the Data Points along the X-Axis
Counting from left to right (from the lowest investment to the highest), we locate the 9th point:
1. 23k: 1 point
2. 30k: 1 point
3. 31k: 1 point
4. 33k: 1 point
5. 37k: 1 point
6. 38k: 1 point
7. 40k: 1 point
8. 42k : There are 2 points at this vertical grid line. These represent the 8th and 9th points.
The 9th point falls exactly on the grid line for 42.
3. Conclusion
The value on the horizontal axis for the 9th point is $\(\mathbf{4 2}\)$. Since the axis is labeled "in thousands," the median amount is $\(\mathbf{\$ 4 2 , 0 0 0}\)$.
Correct Answer: $42,000
1. Identify the Median Position
Since there are $\(\mathbf{1 7}\)$ towns in total, the median is the value in the middle position:
$$
\(\text { Median Position }=\frac{n+1}{2}=\frac{17+1}{2}=9 \text { th town }\)
$$
2. Count the Data Points along the X-Axis
Counting from left to right (from the lowest investment to the highest), we locate the 9th point:
1. 23k: 1 point
2. 30k: 1 point
3. 31k: 1 point
4. 33k: 1 point
5. 37k: 1 point
6. 38k: 1 point
7. 40k: 1 point
8. 42k : There are 2 points at this vertical grid line. These represent the 8th and 9th points.
The 9th point falls exactly on the grid line for 42.
3. Conclusion
The value on the horizontal axis for the 9th point is $\(\mathbf{4 2}\)$. Since the axis is labeled "in thousands," the median amount is $\(\mathbf{\$ 4 2 , 0 0 0}\)$.
Correct Answer: $42,000
Moderators:
