Carcass wrote:
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The figure above represents a triangular field. What is the minimum distance, in meters, that a person would have to walk to go from point A to a point on side BC?
enter your value in metersHere the two sides AB and AC are equal, so we can conclude that
the\({\triangle} ABC\) is isosceles.
Now the minimum length from A to BC will be the perpendicular line.
Since the \({\triangle} ABC\) is isosceles and perpendicular line from A to BC will meet at the midpoint D (as shown in the figure)
Now consider the \({\triangle} ABD\)
AB = 100 , BD =80 and we need to find AD
Using Pythagoras theorem
AD = \(\sqrt{(10000 - 6400)}\) = 60
or we can see that the sides of \({\triangle} ABD\) are in the ratio 3:4:5
= 60:80:100
Ans = 60
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