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The solutions of x2 + x – 20 = 0 are Indicate all possible v
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15 Apr 2018, 03:29
15 Apr 2018, 03:29
Expert Reply
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Question Stats:
86% (00:27) correct
13% (00:43) wrong based on 36 sessions
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The solutions of \(x^2 + x - 20 = 0\) are
Indicate all possible values.
A. –5
B. –4
C. –2
D. –1
E. 4
F. 5
G. 10
Indicate all possible values.
A. –5
B. –4
C. –2
D. –1
E. 4
F. 5
G. 10
Drill 1
Question: 1
Page: 510
Question: 1
Page: 510
Re: The solutions of x2 + x – 20 = 0 are Indicate all possible v
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18 Apr 2018, 15:41
18 Apr 2018, 15:41
1
Expert Reply
Explanation
Factoring this quadratic equation gives you \((x + 5)(x - 4) = 0\).
For the first solution, x + 5 = 0, or x = –5.
For the second solution, x – 4 = 0, or x = 4.
Alternatively, you can PITA to determine which values will satisfy the equation.
Factoring this quadratic equation gives you \((x + 5)(x - 4) = 0\).
For the first solution, x + 5 = 0, or x = –5.
For the second solution, x – 4 = 0, or x = 4.
Alternatively, you can PITA to determine which values will satisfy the equation.
Re: The solutions of x2 + x 20 = 0 are Indicate all possible v
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03 Feb 2026, 06:45
03 Feb 2026, 06:45
1
(x−5)(x+4)
x^2+4x−5x−20=x2−x−20
(x−5)(x+4)not equal to x^2+x−20
so;(x+5)(x−4)=0
(x+5)(x−4)=x^2+x−20
x=−5 or x=4
IMO A & E
x^2+4x−5x−20=x2−x−20
(x−5)(x+4)not equal to x^2+x−20
so;(x+5)(x−4)=0
(x+5)(x−4)=x^2+x−20
x=−5 or x=4
IMO A & E
