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If x is an odd negative integer and y is an even integer,
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Updated on: 10 Feb 2026, 15:40
Updated on: 10 Feb 2026, 15:40
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Question Stats:
31% (02:18) correct
68% (01:53) wrong based on 16 sessions
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If x is an odd negative integer and y is an even integer, which only of the following statements must be true?
I. \((3 x-2 y) \)is odd
II. \(x y^2 \)is an even negative integer
III. \(\left(y^2-x\right)\) is an odd negative integer
A. I
B. II only
C. I and II
D. I and III
E. II and III
I. \((3 x-2 y) \)is odd
II. \(x y^2 \)is an even negative integer
III. \(\left(y^2-x\right)\) is an odd negative integer
A. I
B. II only
C. I and II
D. I and III
E. II and III
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Re: If x is an odd negative integer and y is an even integer,
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10 Feb 2026, 10:44
10 Feb 2026, 10:44
Carcass
x = -ve (odd)
y = even integer
I) 3x is odd and 2y is even so its gonna be odd
II) y^2 is positive even integer and x is odd negative so x*y^2 is even negative integer
III)y^2 is positive even and -x is odd positive so its gonna be odd positive
I and II are true
the given OA is only A. it should be C
x = -ve (odd)
y = even integer
I) 3x is odd and 2y is even so its gonna be odd
II) y^2 is positive even integer and x is odd negative so x*y^2 is even negative integer
III)y^2 is positive even and -x is odd positive so its gonna be odd positive
I and II are true
the given OA is only A. it should be C
Re: If x is an odd negative integer and y is an even integer,
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10 Feb 2026, 15:39
10 Feb 2026, 15:39
Expert Reply
You did not take into account that y could be also zero
A is the answer
A is the answer
