GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 17Live Online Classes with Top GRE Expert Rich Zwelling
08:00 PM EST
-10:00 PM EST
Get live instruction from a top-scoring, industry-recognized GRE teachers + 6 months of access to TTP Self-Study included! Tues/Thur Sept 7, 2026---Feb. 2, 2027, 1:00pm-3:00pm EST
Dec 14Live Online Classes with Top GRE Expert Michael Butville
08:00 PM EST
-10:00 PM EST
Get live instruction from a top-scoring, industry-recognized GRE teachers + 6 months of access to TTP Self-Study included! Mon/Wed Dec. 14, 2026---Feb. 22, 2027, 8:00pm-10:00pm EST
The average (arithmetic mean) of fifteen consecutive integer
[#permalink]
29 Aug 2018, 16:40
29 Aug 2018, 16:40
1
Expert Reply
10
Bookmarks
00:00
Question Stats:
81% (01:34) correct
18% (01:41) wrong based on 44 sessions
Hide Show timer Statistics
The average (arithmetic mean) of fifteen consecutive integers is 88. What is the greatest of these integers?
Show: :: OA
95
Re: The average (arithmetic mean) of fifteen consecutive integer
[#permalink]
30 Aug 2018, 01:08
30 Aug 2018, 01:08
2
1st number = x
2nd number = x+1
3rd number = x+2
15th number = x+14
avg = \(\frac{x+14+x}{2} = 88\)
or, \(\frac{2x+14}{2} = 88\)
or, \(x+7 = 88\)
or, \(x = 81\)
since the largest number is \(x+14\) it is 81 + 14 = 95
2nd number = x+1
3rd number = x+2
15th number = x+14
avg = \(\frac{x+14+x}{2} = 88\)
or, \(\frac{2x+14}{2} = 88\)
or, \(x+7 = 88\)
or, \(x = 81\)
since the largest number is \(x+14\) it is 81 + 14 = 95
Retired Moderator
Joined: 02 Jan 2020
Status:GRE Quant Tutor
Posts: 1141
Given Kudos: 9
Location: India
Concentration: General Management
Schools: XLRI Jamshedpur, India - Class of 2014
GMAT 1: 700 Q51 V31
GPA: 2.8
WE:Engineering (Computer Software)
Re: The average (arithmetic mean) of fifteen consecutive integer
[#permalink]
16 Sep 2022, 22:58
16 Sep 2022, 22:58
2
Given that The average (arithmetic mean) of fifteen consecutive integers is 88 and we need to find the greatest of these integers
============================================================
Theory
============================================================
Let the middle term be x
=> Mean = middle term = x = 88
Now, the numbers are consecutive so the greatest or the last term will be 7 more than the middle term = x + 7 = 88 + 7 = 95
So, Answer will be 95.
Hope it helps!
Watch the following video to Learn the Basics of Statistics
============================================================
Theory
- ‣‣‣ In Case of consecutive number Mean = Middle term
============================================================
Let the middle term be x
=> Mean = middle term = x = 88
Now, the numbers are consecutive so the greatest or the last term will be 7 more than the middle term = x + 7 = 88 + 7 = 95
So, Answer will be 95.
Hope it helps!
Watch the following video to Learn the Basics of Statistics
