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In the below addition
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06 Nov 2025, 04:33
06 Nov 2025, 04:33
Expert Reply
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Question Stats:
71% (02:55) correct
28% (02:27) wrong based on 21 sessions
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In the below addition $\(\mathrm{A}, \mathrm{B}, \mathrm{C}, \mathrm{D}, \mathrm{E}, \mathrm{F}\)$, and G represent the digits $\(0,1,2,3,4,5\)$ and 6 . If each variable has a different value, and $\(E \neq 0\)$, then $G$ equals
\(\begin{array}{r}
A B \\
+C D \\
\hline E F G
\end{array}\)
A. 2
B. 3
C. 4
D. 5
E. 6
\(\begin{array}{r}
A B \\
+C D \\
\hline E F G
\end{array}\)
A. 2
B. 3
C. 4
D. 5
E. 6
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Re: In the below addition
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10 Dec 2025, 10:15
10 Dec 2025, 10:15
Expert Reply
1
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There are several valid assignments of digits that satisfy the puzzle, and in all of them $G=5$.
Reasoning
The equation is $\(\overline{A B}+\overline{C D}=\overline{E F G}\)$, with digits 0-6 used exactly once and $\(E \neq 0\)$.
Enumerating all possibilities under these constraints gives the valid solutions $\((A, B, C, D, E, F, G)= (4,2,6,3,1,0,5),(4,3,6,2,1,0,5),(6,2,4,3,1,0,5),(6,3,4,2,1,0,5)\)$, and in each case $G=5$.
Therefore, the correct choice is D. 5.
Reasoning
The equation is $\(\overline{A B}+\overline{C D}=\overline{E F G}\)$, with digits 0-6 used exactly once and $\(E \neq 0\)$.
Enumerating all possibilities under these constraints gives the valid solutions $\((A, B, C, D, E, F, G)= (4,2,6,3,1,0,5),(4,3,6,2,1,0,5),(6,2,4,3,1,0,5),(6,3,4,2,1,0,5)\)$, and in each case $G=5$.
Therefore, the correct choice is D. 5.
Re: In the below addition
[#permalink]
19 Apr 2026, 01:21
19 Apr 2026, 01:21
Is there a simpler, more mathematical way to solve this?
