GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 17Live Online Classes with Top GRE Expert Rich Zwelling
08:00 PM EST
-10:00 PM EST
Get live instruction from a top-scoring, industry-recognized GRE teachers + 6 months of access to TTP Self-Study included! Tues/Thur Sept 7, 2026---Feb. 2, 2027, 1:00pm-3:00pm EST
Dec 14Live Online Classes with Top GRE Expert Michael Butville
08:00 PM EST
-10:00 PM EST
Get live instruction from a top-scoring, industry-recognized GRE teachers + 6 months of access to TTP Self-Study included! Mon/Wed Dec. 14, 2026---Feb. 22, 2027, 8:00pm-10:00pm EST
xyz < 0
[#permalink]
20 Oct 2017, 02:40
20 Oct 2017, 02:40
Expert Reply
00:00
Question Stats:
77% (00:45) correct
22% (00:44) wrong based on 67 sessions
Hide Show timer Statistics
\(xyz < 0\)
Quantity A |
Quantity B |
\(x + y + z\) |
\(2x + 2y + 2z\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: xyz < 0
[#permalink]
20 Oct 2017, 06:17
20 Oct 2017, 06:17
The fact that xyz < 0 does not give enough information about the unknowns to be able to compare the two quantities. We just know that two of them should be positive and the other negative but nothing more. Given that we can't compare the quantities answer is D!
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
xyz < 0
[#permalink]
31 May 2020, 06:07
31 May 2020, 06:07
1
Carcass wrote:
\(xyz < 0\)
Quantity A |
Quantity B |
\(x + y + z\) |
\(2x + 2y + 2z\) |
Let's test some possible values of x, y and z
case i: Since \(xyz < 0\), it could be the case that \(x=1\), \(y=1\) and \(z=-1\)
We get:
Quantity A: \(x + y + z = 1 + 1 + (-1) = 1\)
Quantity B: \(2(1) + 2(1) + 2(-1) = 2\)
In this case, Quantity B is greater
case -i: Since \(xyz < 0\), it could be the case that \(x=-1\), \(y=-1\) and \(z=-1\)
We get:
Quantity A: \(x + y + z = (-1) + (-1) + (-1) = -3\)
Quantity B: \(2(-1) + 2(-1) + 2(-1) = -6\)
In this case, Quantity A is greater
Answer: D
RELATED VIDEO FROM OUR COURSE
