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Set T consists of all multiples of 5 from 30 to 225 inclusiv
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22 Oct 2017, 06:06
22 Oct 2017, 06:06
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Question Stats:
77% (00:57) correct
22% (01:21) wrong based on 44 sessions
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Set T consists of all multiples of 5 from 30 to 225 inclusive
A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Kudos for correct solution.
Quantity A |
Quantity B |
Mean of Set T |
Median of Set T |
A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Kudos for correct solution.
Re: Set T consists of all multiples of 5 from 30 to 225 inclusiv
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22 Oct 2017, 09:00
22 Oct 2017, 09:00
1
The mean of set S is computed as \(\frac{\frac{40}{2}(30+225)}{40} = 127.5\) using the formula for the sum of an arithmetic series at the numerator. The median of S, given that S has 40 elements, is the mean of the 20 and 21 elements of the series, i.e. \(\frac{125+130}{2} = 127.5\). Then quantities A and B are equal and answer is C
Re: Set T consists of all multiples of 5 from 30 to 225 inclusiv
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23 Mar 2019, 16:48
23 Mar 2019, 16:48
1
IlCreatore wrote:
The mean of set S is computed as \(\frac{\frac{40}{2}(30+225)}{40} = 127.5\) using the formula for the sum of an arithmetic series at the numerator. The median of S, given that S has 40 elements, is the mean of the 20 and 21 elements of the series, i.e. \(\frac{125+130}{2} = 127.5\). Then quantities A and B are equal and answer is C
Any set that is evenly distributed will have mean = median. In this case, the list os equally distributed as a multiple of 5. Ans - C
