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GRE Math Challenge #36 - x = v +2
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Updated on: 18 Feb 2020, 10:09
Updated on: 18 Feb 2020, 10:09
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Question Stats:
65% (01:08) correct
34% (01:02) wrong based on 204 sessions
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\(x=v+2 \)
\(y=2v\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
\(y=2v\)
Quantity A |
Quantity B |
\( x^2+y^2\) |
(\(x+y)^2 \) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
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Re: GRE Math Challenge #36
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18 May 2015, 15:07
18 May 2015, 15:07
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sandy wrote:
\(x=v+2 \)
\(y=2v\)
\(y=2v\)
Quantity A |
Quantity B |
\( x^2+y^2\) |
(\(x+y)^2 \) |
For the moment, let's skip the given information and see if we can simplify the two quantities.
Quantity A: x² + y²
Quantity B: (x + y)²
Expand quantity B to get:
Quantity A: x² + y²
Quantity B: x² + 2xy + y²
Subtract x² and y² from both quantities to get:
Quantity A: 0
Quantity B: 2xy
NOW, replace x and y with the given values to get:
Quantity A: 0
Quantity B: 2(v + 2)(2v)
Expand quantity B to get:
Quantity A: 0
Quantity B: (2v + 4)(2v) = 4v² + 8v
Now consider these two conflicting cases:
case #1: v = 0
We get:
Quantity A: 0
Quantity B: 4v² + 8v = 4(0)² + 8(0) = 0
The quantities are EQUAL
case #2: v = 1
We get:
Quantity A: 0
Quantity B: 4v² + 8v = 4(1)² + 8(1) = 12
The quantities are NOT EQUAL
Answer:
Show: ::
D
Cheers,
Brent
General Discussion
Re: GRE Math Challenge #36
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03 Mar 2018, 23:05
03 Mar 2018, 23:05
GreenlightTestPrep wrote:
sandy wrote:
For the moment, let's skip the given information and see if we can simplify the two quantities.
Quantity A: x² + y²
Quantity B: (x + y)²
Expand quantity B to get:
Quantity A: x² + y²
Quantity B: x² + 2xy + y²
Subtract x² and y² from both quantities to get:
Quantity A: 0
excellent explanation
Quantity B: 2xy
NOW, replace x and y with the given values to get:
Quantity A: 0
Quantity B: 2(v + 2)(2v)
Expand quantity B to get:
Quantity A: 0
Quantity B: (2v + 4)(2v) = 4v² + 8v
Now consider these two conflicting cases:
case #1: v = 0
We get:
Quantity A: 0
Quantity B: 4v² + 8v = 4(0)² + 8(0) = 0
The quantities are EQUAL
case #2: v = 1
We get:
Quantity A: 0
Quantity B: 4v² + 8v = 4(1)² + 8(1) = 12
The quantities are NOT EQUAL
Answer:
Show: ::
D
Cheers,
Brent
