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\frac{4+\sqrt{15}}{(4-\sqrt{15})^3}
[#permalink]
30 Sep 2026, 04:04
30 Sep 2026, 04:04
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Quantity A |
Quantity B |
\( \frac{4+\sqrt{15}}{(4-\sqrt{15})^3}\) |
\(\frac{6+\sqrt{35}}{(6-\sqrt{35})^2}\) |
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
- Part of the project: GRE Daily Quant Challenge ALL 4 CORE QUANT AREAS
- Also replying to the unanswered questions
gmatclubot
\frac{4+\sqrt{15}}{(4-\sqrt{15})^3} [#permalink]
30 Sep 2026, 04:04
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