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Given that x/y>1
[#permalink]
12 Sep 2026, 02:31
12 Sep 2026, 02:31
Expert Reply
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Question Stats:
60% (01:34) correct
40% (00:59) wrong based on 10 sessions
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Given that \( \frac{x}{y}>1 \)
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(\frac{x}{y}+\frac{y}{x}\) |
2 |
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
- Part of the project: GRE Daily Quant Challenge ALL 4 CORE QUANT AREAS
- Also replying to the unanswered questions
Re: Given that x/y>1
[#permalink]
01 Oct 2026, 00:06
01 Oct 2026, 00:06
Expert Reply
We are given:
\(\frac{x}{y}>1\)
This implies x and y have the same sign, and \(|x|>|y|\) , with \(y \neq 0\) .
Let:
\(t=\frac{x}{y}>1\)
Then:
\(\frac{x}{y}+\frac{y}{x}=t+\frac{1}{t}\)
For \( t>1\) ,
\(t+\frac{1}{t}>2\)
So Quantity A is greater than Quantity B (2).
A) Quantity A is greater.
Answer: (A)
\(\frac{x}{y}>1\)
This implies x and y have the same sign, and \(|x|>|y|\) , with \(y \neq 0\) .
Let:
\(t=\frac{x}{y}>1\)
Then:
\(\frac{x}{y}+\frac{y}{x}=t+\frac{1}{t}\)
For \( t>1\) ,
\(t+\frac{1}{t}>2\)
So Quantity A is greater than Quantity B (2).
A) Quantity A is greater.
Answer: (A)
gmatclubot
Re: Given that x/y>1 [#permalink]
01 Oct 2026, 00:06
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