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Solution X is 10 percent alcohol by volume, and solution Y
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26 Oct 2017, 02:33
26 Oct 2017, 02:33
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Question Stats:
84% (17:37) correct
15% (03:26) wrong based on 51 sessions
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Solution X is 10 percent alcohol by volume, and solution Y is 30 percent alcohol by volume. How many milliliters of solution Y must be added to 200 milliliters of solution X to create a solution that is 25 percent alcohol by volume?
A. 250/3
B. 500/3
C. 400
D. 480
E. 600
Kudos for correct solution.
A. 250/3
B. 500/3
C. 400
D. 480
E. 600
Kudos for correct solution.
Re: Solution X is 10 percent alcohol by volume, and solution Y
[#permalink]
26 Oct 2017, 04:44
26 Oct 2017, 04:44
3
The problem can be solved using the formula for the weighted average as \(\frac{200*0.10+x*0.3}{200+x} = 0.25\), where x is the amount of solution Y needed to reach a 25% concentration in the mix. Solving, we get x = 600 thus answer E
Re: Solution X is 10 percent alcohol by volume, and solution Y
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26 Jun 2025, 19:05
26 Jun 2025, 19:05
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