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Regular pentagon P has all five diagonals drawn. What is th
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26 Oct 2017, 23:39
26 Oct 2017, 23:39
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Regular pentagon P has all five diagonals drawn. What is the angle between two of these diagonals where they meet at a vertex of the pentagon?
(A) 12°
(B) 36°
(C) 54°
(D) 60°
(E) 72°
Kudos for correct solution.
(A) 12°
(B) 36°
(C) 54°
(D) 60°
(E) 72°
Kudos for correct solution.
Re: Regular pentagon P has all five diagonals drawn. What is th
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27 Oct 2017, 04:51
27 Oct 2017, 04:51
1
Let's start from the fact that the sum of interior angles of a regular polygon is always computed as \((n-2)*180°\), where n is the number of sides. Thus, the sum of interior angles of a pentagon is 3*180 = 540°, so that, because it is regular, each of its angles is 108° (540/5).
Then, at a vertex where two diagonals meet, the angle is divided in three equal portions, so that the angle between the two diagonals measures 108/3 = 36°.
Answer B
Then, at a vertex where two diagonals meet, the angle is divided in three equal portions, so that the angle between the two diagonals measures 108/3 = 36°.
Answer B
Re: Regular pentagon P has all five diagonals drawn. What is th
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26 Oct 2022, 06:48
26 Oct 2022, 06:48
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