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A combination lock has three dials, each consisting of a sin
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29 Oct 2017, 02:19
29 Oct 2017, 02:19
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88% (01:06) correct
11% (02:06) wrong based on 18 sessions
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A combination lock has three dials, each consisting of a single digit, 0-9. The lock can be opened only if each dial is in the correct position. If the code for the lock consists of three prime numbers, what is the probability that 252 is the code? (Provide answer in fraction form).
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1/64
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Re: A combination lock has three dials, each consisting of a sin
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30 Oct 2017, 10:02
30 Oct 2017, 10:02
2
The prime numbers made of 1 digit are 2, 3, 5, 7. Thus, for each dial of the code there are 4 choices so that the number of possible codes is 4*4*4 = 64. Thus, the probability of one specific code out of 64 possible codes is 1/64.
gmatclubot
Re: A combination lock has three dials, each consisting of a sin [#permalink]
30 Oct 2017, 10:02
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