Given: \((4^2)^3 \times 2^6=2^y\)
Apply the Power of a Power law to the left side to get: \(4^6 \times 2^6=2^y\)
Rewrite \(4\) as \(2^2\) to get: \((2^2)^6 \times 2^6=2^y\)
Apply the Power of a Power law to the left side to get: \(2^{12} \times 2^6=2^y\)
Apply the Product law to get: \(2^{18} =2^y\)
Since the bases are the same, the exponents must be the same, which means \(18 = y\)

Answer: C