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In the diagram, AC = 6. CE = 12, DF = 4, and AB is parallel
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12 Nov 2017, 01:37
12 Nov 2017, 01:37
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In the diagram, AC = 6. CE = 12, DF = 4, and AB is parallel to DE.
A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Kudos for correct solution.
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Re: In the diagram, AC = 6. CE = 12, DF = 4, and AB is parallel
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12 Nov 2017, 09:43
12 Nov 2017, 09:43
The two triangles ABC and CDE are similar because they have all the three angles equal. Then, the fact that AC is half CE means that all the corresponding lengths in triangle ABC are half those of triangle CDE. Then, given DF, the height of CDE, equal to 4, the height of triangle ABC must be 2.
Thus, its area is computed as (6*2)/2 = 6. Quantity B is greater.
Answer B
Thus, its area is computed as (6*2)/2 = 6. Quantity B is greater.
Answer B
Re: In the diagram, AC = 6. CE = 12, DF = 4, and AB is parallel
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07 Dec 2017, 23:26
07 Dec 2017, 23:26
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IlCreatore wrote:
The two triangles ABC and CDE are similar because they have all the three angles equal. Then, the fact that AC is half CE means that all the corresponding lengths in triangle ABC are half those of triangle CDE. Then, given DF, the height of CDE, equal to 4, the height of triangle ABC must be 2.
Thus, its area is computed as (6*2)/2 = 6. Quantity B is greater.
Answer B
Thus, its area is computed as (6*2)/2 = 6. Quantity B is greater.
Answer B
How do I know they are similar triangle?
Because two line are intercept, and the third line is parallel?
