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m and n are integers.

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Carcass
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m and n are integers. [#permalink] New post   07 Dec 2017, 03:16
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m and n are integers.

Quantity A
Quantity B
\((\sqrt{10^{2m}})(\sqrt{10^{2n}})\)
\(10^{mn}\)


A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal
D. The relationship cannot be determined from the information given.
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D
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Re: m and n are integers. [#permalink] New post   08 Dec 2017, 10:59
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Carcass wrote:
m and n are integers.

Quantity A
Quantity B
\((\sqrt{10^{2m}})(\sqrt{10^{2n}})\)
\(10^{mn}\)


A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal
D. The relationship cannot be determined from the information given.



RULE: √x = x^(1/2)

So, √[10^(2m)] = [10^(2m)]^(1/2)
= 10^m [once we apply the Power of a Power rule]

Likewise, √[10^(2n)] = [10^(2n)]^(1/2)
= 10^n [once we apply the Power of a Power rule]

We get:

QUANTITY A: (10^m)(10^n)
QUANTITY B: 10^(mn)

Simplify to get:
QUANTITY A: 10^(m+n)
QUANTITY B: 10^(mn)

Let's test some values of m and n

m = 0 and n = 0
We get:
QUANTITY A: 10^(0+0) = 10^0 = 1
QUANTITY B: 10^[(0)(0)] = 10^0 = 1
In this case the two quantities are equal

m = 1 and n = 1
We get:
QUANTITY A: 10^(1+1) = 10^2 = 100
QUANTITY B: 10^[(1)(1)] = 10^1 = 10
In this case Quantity is greater

Answer: D

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Re: m and n are integers. [#permalink] New post   07 Dec 2017, 21:01
Can anyone explain this? thank you
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simon1994
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Re: m and n are integers. [#permalink] New post   08 Dec 2017, 05:13
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Hello,

for this question it is best to try out different values.

For instance.

If m and n are both zero, both expressions will be equal to 1 (since anything exponent zero is one) => Answer C
If m and n are both 3, Qty A becomes 10^6 and Qty B becomes 10^9 => Answer B,

since the square root and exponent 2 cancel each other out, Qty A becomes 10^m * 10^n => 10^(m+n)= 10^(3+3)<10^(3*3)

Hence overall answer is D
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Re: m and n are integers. [#permalink] New post   26 Jun 2021, 03:06
Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: m and n are integers. [#permalink]
26 Jun 2021, 03:06
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