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A set of six numbers consists of x, x + 3, x + 5, x + 7, x
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Updated on: 10 Jun 2021, 08:25
Updated on: 10 Jun 2021, 08:25
Expert Reply
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Question Stats:
64% (00:37) correct
36% (00:39) wrong based on 25 sessions
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A set of six numbers consists of x, x + 3, x + 5, x + 7, x + 11, and x + 13. What is the median of this set, in terms of x ?
A. x + 5
B. x + 6
C. x + 6.5
D. 3x + 8
E. 6x + 39
A. x + 5
B. x + 6
C. x + 6.5
D. 3x + 8
E. 6x + 39
Drill 3
Question: 3
Page: 528
Question: 3
Page: 528
Re: A set of six numbers consists of x, x + 3, x + 5, x + 7, x
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29 Dec 2017, 14:17
29 Dec 2017, 14:17
Expert Reply
Explanation
Since there are variables in the answer choices, try plugging in 2 for x. Your two middle numbers are now 7 and 9, and the median is their average, 8. Circle 8 as your target answer.
After you check all the choices, only choice B matches.
Since there are variables in the answer choices, try plugging in 2 for x. Your two middle numbers are now 7 and 9, and the median is their average, 8. Circle 8 as your target answer.
After you check all the choices, only choice B matches.
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A set of six numbers consists of x, x + 3, x + 5, x + 7, x
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15 Jan 2020, 16:28
15 Jan 2020, 16:28
1
sandy wrote:
A set of six numbers consists of x, x + 3, x + 5, x + 7, x + 11, and x + 13. What is the median of this set, in terms of x ?
A. x + 5
B. x + 6
C. x + 6.5
D. 3x + 8
E. 6x + 39
A. x + 5
B. x + 6
C. x + 6.5
D. 3x + 8
E. 6x + 39
Drill 3
Question: 3
Page: 528
Question: 3
Page: 528
Notice that the six values all already listed in ascending order
That is: x < x + 3 < x + 5 < x + 7 < x + 11 < x + 13
Since we have an EVEN number of values, the median will be the average of the two middlemost values.
So, the median = ((x + 5) + (x + 7))/2
= (2x + 12)/2
= x + 6
Answer: B
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