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John will spend the summer in one of the houses either on
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09 Dec 2017, 19:21
09 Dec 2017, 19:21
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Question Stats:
20% (02:42) correct
80% (02:18) wrong based on 35 sessions
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John will spend the summer in one of the houses either on Surf Street or Breaker Way. Surf Street has 1 landside house and 4 beachside houses, and Breaker Way has 1 beachside house and 2 landside houses. A sea turtle randomly lays eggs in front of a beachside house on Surf Street, and another sea turtle randomly lays eggs in front of a beachside house on Breaker Way. What are the probabilities that a sea turtle lays its eggs in front of John’s house, depending on which street he lives on?
A. \(\frac{4}{25}\)
B. \(\frac{1}{5}\)
C. \(\frac{4}{15}\)
D. \(\frac{1}{3}\)
E. \(\frac{17}{25}\)
A. \(\frac{4}{25}\)
B. \(\frac{1}{5}\)
C. \(\frac{4}{15}\)
D. \(\frac{1}{3}\)
E. \(\frac{17}{25}\)
Show: :: OA
B, D
Drill 3
Question: 5
Page: 528-529
Question: 5
Page: 528-529
Re: John will spend the summer in one of the houses either on
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29 Dec 2017, 14:22
29 Dec 2017, 14:22
1
Expert Reply
Explanation
If you pare down the problem, then it is much simpler than it first appears. There will be 1 house on Surf Street at which a turtle will lay its eggs; this is “the number of outcomes you want.”
There are a total of 5 houses, which is the “total number of possible outcomes.” Therefore, if John spends the summer on Surf Street, the probability of John staying in the house where the sea turtle will lay its eggs is choice B, \(\frac{1}{5}\), and the information about the landside houses versus seaside houses actually turns out to be unnecessary.
Similarly, if John stays on Breaker Way, there will be 1 house that a turtle will lay its eggs at out of a total of 3 possible houses that John could live in. Therefore, if he lives on Breaker Way, there is a \(\frac{1}{3}\)chance that the turtle lays its eggs outsides John’s house, and this makes choice D correct.
If you pare down the problem, then it is much simpler than it first appears. There will be 1 house on Surf Street at which a turtle will lay its eggs; this is “the number of outcomes you want.”
There are a total of 5 houses, which is the “total number of possible outcomes.” Therefore, if John spends the summer on Surf Street, the probability of John staying in the house where the sea turtle will lay its eggs is choice B, \(\frac{1}{5}\), and the information about the landside houses versus seaside houses actually turns out to be unnecessary.
Similarly, if John stays on Breaker Way, there will be 1 house that a turtle will lay its eggs at out of a total of 3 possible houses that John could live in. Therefore, if he lives on Breaker Way, there is a \(\frac{1}{3}\)chance that the turtle lays its eggs outsides John’s house, and this makes choice D correct.
Re: John will spend the summer in one of the houses either on
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06 May 2021, 12:52
06 May 2021, 12:52
But sandy the turtle can lay eggs in front of beach houses only then how we can include landslide houses??
As per my understanding answer should be only 1/5 as there are 5 beach houses in total
As per my understanding answer should be only 1/5 as there are 5 beach houses in total
