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The odds in favor of winning a game can be found by
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09 May 2015, 10:24
09 May 2015, 10:24
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84% (00:40) correct
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The odds in favor of winning a game can be found by computing the ratio of the probability of wining to the probability of not winning. if the probability that Pat will win a game is \(\frac{4}{9}\) , what are the odds that Pat will win the game?
(A) 4 to 5
(B) 4 to 9
(C) 5 to 4
(D) 5 to 9
(E) 9 to 5
Kudos for the right answer and explanation
(A) 4 to 5
(B) 4 to 9
(C) 5 to 4
(D) 5 to 9
(E) 9 to 5
Kudos for the right answer and explanation
Re: GRE Math Challenge #83-The odds in favor of winning a game
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14 Dec 2017, 08:49
14 Dec 2017, 08:49
1
sandy wrote:
The odds in favor of winning a game can be found by computing the ratio of the probability of wining to the probability of not winning. if the probability that Pat will win a game is 4/9 , what are the odds that Pat will win the game?
(A) 4 to 5
(B) 4 to 9
(C) 5 to 4
(D) 5 to 9
(E) 9 to 5
(A) 4 to 5
(B) 4 to 9
(C) 5 to 4
(D) 5 to 9
(E) 9 to 5
Here odds in favor of winning a game = \(\frac{probability of wining}{probability of not winning}\).
Now,
Let W =probability of wining
and N=probability of not winning
Since probability of winning the game W = \(\frac{4}{9}\),
Therefore the probability of not winning a game N = \(\frac{5}{9}\) \((1-\frac{4}{9})\)
Hence the odds in favor of winning a game = \(\frac{W}{N}\) = \(\frac{4}{9} * \frac{9}{5}\) = \(\frac{4}{5}\)
Re: The odds in favor of winning a game can be found by
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11 Dec 2019, 15:29
11 Dec 2019, 15:29
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Bump for further discussion
