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Practice Question#5-A rectangle is formed by increasing
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02 Sep 2015, 20:10
02 Sep 2015, 20:10
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Question Stats:
71% (00:26) correct
28% (01:09) wrong based on 14 sessions
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A rectangle is formed by increasing two opposite sides of a square of side length x by y units, and decreasing the two remaining sides of the square by y units. What is the area of the rectangle?
A,4x
B,4x – 2y
C,x^2 – 2y
D,x^2 + 2y
E,x^2 – y^2
No idea how to solve?Why should I consider x+y and x-y
A,4x
B,4x – 2y
C,x^2 – 2y
D,x^2 + 2y
E,x^2 – y^2
No idea how to solve?Why should I consider x+y and x-y
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: Practice Question#5
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11 Sep 2015, 09:26
11 Sep 2015, 09:26
1
victory wrote:
A rectangle is formed by increasing two opposite sides of a square of side length x by y units, and decreasing the two remaining sides of the square by y units. What is the area of the rectangle?
A,4x
B,4x – 2y
C,x^2 – 2y
D,x^2 + 2y
E,x^2 – y^2
A,4x
B,4x – 2y
C,x^2 – 2y
D,x^2 + 2y
E,x^2 – y^2
ORIGINALLY the sides of the square have length x
Then we make some changes.
We INCREASE the length of two opposite sides by y units.
So, new length = x + y
We DECREASE the length of two opposite sides by y units.
So, new length = x - y
We now have a rectangle.
The AREA of this rectangle = (x + y)(x - y)
= x^2 - y^2
= E
Cheers,
Brent - Greenlight Test Prep
gmatclubot
Re: Practice Question#5 [#permalink]
11 Sep 2015, 09:26
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