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|2y -5|<1

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Carcass
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|2y -5|<1 [#permalink] New post   21 Dec 2017, 16:54
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\(|2y -5|<1\)

Quantity A
Quantity B
y
1


A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal
D. The relationship cannot be determined from the information given.

kudo for the right solution and explanation
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A
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Re: |2y -5|<1 [#permalink] New post   21 Dec 2017, 23:39
1
2y - 5 < 1
So 2y < 6
Y < 2
So Y could be 1 so C but can be also less so Answer D
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Re: |2y -5|<1 [#permalink] New post   22 Dec 2017, 08:54
2
Carcass wrote:
\(|2y -5|<1\)

Quantity A
Quantity B
y
1


A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal
D. The relationship cannot be determined from the information given.

kudo for the right solution and explanation



Here we have to consider negative and positive value of |2y -5|.

Considering (2y - 5) to be negative

or -(2y - 5) < 1

or 2y - 5 > -1 (equality changes as the sign changes)

or 2y > 4 (adding 5 on both side)

or y > 2

Now consider positive

|2y -5|<1

or 2y - 5 < 1

or 2y < 6 (adding 5 on both side)

or y <3

Therefore the value of y is = 2 < y < 3

Hence statement A.
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GreenlightTestPrep
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Re: |2y -5|<1 [#permalink] New post   09 Jan 2018, 12:45
3
Carcass wrote:
\(|2y -5|<1\)

Quantity A
Quantity B
y
1




When solving inequalities involving ABSOLUTE VALUE, there are 2 things you need to know:
Rule #1: If |something| < k, then –k < something < k
Rule #2: If |something| > k, then EITHER something > k OR something < -k
Note: these rules assume that k is positive

Given: |2y - 5| < 1
So, by Rule #1, we get: -1 < 2y - 5 < 1
Add 5 to all sides to get: 4 < 2y < 6
Divide all sides by 2 to get: 2 < y < 3

Since y is between 2 and 3, y MUST be greater than 1

Answer: A

Cheers,
Brent
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abhay98421
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Re: |2y -5|<1 [#permalink] New post   03 Feb 2018, 03:54
Could you suggest the tougher inequalities and absolute problems for practice?
I take the GRE in 2 weeks and I keep getting problems in absolute/inequalities wrong.
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Re: |2y -5|<1 [#permalink] New post   04 Feb 2018, 14:49
Expert Reply
Just click on the tag above the question "absolute value" and you do have all the questions present on the board

Here https://gre.myprepclub.com/forum/search.ph ... tag_id=234

Also. here on the correct usage of the tags https://gre.myprepclub.com/forum/using-tag ... tml#p15585

Regards
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sandeeps
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Re: |2y -5|<1 [#permalink] New post   07 Feb 2018, 02:35
Answer: A
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GREMasterBlaster
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Re: |2y -5|<1 [#permalink] New post   17 Feb 2018, 01:12
pranab01 wrote:
Carcass wrote:
\(|2y -5|<1\)

Quantity A
Quantity B
y
1


A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal
D. The relationship cannot be determined from the information given.

kudo for the right solution and explanation



Here we have to consider negative and positive value of |2y -5|.

Considering (2y - 5) to be negative

or -(2y - 5) < 1

or 2y - 5 > -1 (equality changes as the sign changes)

or 2y > 4 (adding 5 on both side)

or y > 2

Now consider positive

|2y -5|<1

or 2y - 5 < 1

or 2y < 6 (adding 5 on both side)

or y <3

Therefore the value of y is = 2 < y < 3

Hence statement A.


I used same method, and yes that's correct answer. Choice A
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matayo
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Re: |2y -5|<1 [#permalink] New post   17 Feb 2018, 16:07
GreenlightTestPrep wrote:
Carcass wrote:
\(|2y -5|<1\)

Quantity A
Quantity B
y
1




When solving inequalities involving ABSOLUTE VALUE, there are 2 things you need to know:
Rule #1: If |something| < k, then –k < something < k
Rule #2: If |something| > k, then EITHER something > k OR something < -k
Note: these rules assume that k is positive

Given: |2y - 5| < 1
So, by Rule #1, we get: -1 < 2y - 5 < 1
Add 5 to all sides to get: 4 < 2y < 6
Divide all sides by 2 to get: 2 < y < 3

Since y is between 2 and 3, y MUST be greater than 1

Answer: A

Cheers,
Brent


thanks for the insight
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Re: |2y -5|<1 [#permalink]
17 Feb 2018, 16:07
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