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Depending on the night, a pizza restaurant offers anywhere
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Updated on: 12 Jan 2018, 15:22
Updated on: 12 Jan 2018, 15:22
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Question Stats:
64% (01:20) correct
35% (01:22) wrong based on 64 sessions
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Depending on the night, a pizza restaurant offers anywhere from seven to nine different choices of toppings. Sam wants a pizza with three toppings. Which of the following could be the number of different ways that Sam can order his pizza with three different toppings?
Indicate all possible values.
A. 35
B. 42
C. 56
D. 84
E. 210
F. 252
G. 504
Indicate all possible values.
A. 35
B. 42
C. 56
D. 84
E. 210
F. 252
G. 504
Drill 1
Question: 13
Page: 361
Question: 13
Page: 361
Show: :: OA
A, B, D
Re: Depending on the night, a pizza restaurant offers anywhere
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Updated on: 12 Jan 2018, 15:21
Updated on: 12 Jan 2018, 15:21
2
Expert Reply
Explanation
This problem is about combinations, because order doesn’t matter. On a night when the pizza place offers only seven toppings, Sam has (7 × 6 × 5) ÷ (1 × 2 × 3) = 35 options, choice A.
When the pizza place has eight toppings, Sam has (8 × 7 × 6) ÷ (1 × 2 × 3) = 56 options, choice C. And when the pizza place has nine toppings, Sam has (9 × 8 × 7) ÷ (1 × 2 × 3) = 84 options, choice D.
This problem is about combinations, because order doesn’t matter. On a night when the pizza place offers only seven toppings, Sam has (7 × 6 × 5) ÷ (1 × 2 × 3) = 35 options, choice A.
When the pizza place has eight toppings, Sam has (8 × 7 × 6) ÷ (1 × 2 × 3) = 56 options, choice C. And when the pizza place has nine toppings, Sam has (9 × 8 × 7) ÷ (1 × 2 × 3) = 84 options, choice D.
Re: Depending on the night, a pizza restaurant offers anywhere
[#permalink]
08 Jan 2018, 19:29
08 Jan 2018, 19:29
sandy wrote:
Explanation
This problem is about combinations, because order doesn’t matter. On a night when the pizza place offers only seven toppings, Sam has (7 × 6 × 5) ÷ (1 × 2 × 3) = 35 options, choice A.
When the pizza place has eight toppings, Sam has (8 × 7 × 6) ÷ (1 × 2 × 3) = 56 options, choice B. And when the pizza place has nine toppings, Sam has (9 × 8 × 7) ÷ (1 × 2 × 3) = 84 options, choice D.
This problem is about combinations, because order doesn’t matter. On a night when the pizza place offers only seven toppings, Sam has (7 × 6 × 5) ÷ (1 × 2 × 3) = 35 options, choice A.
When the pizza place has eight toppings, Sam has (8 × 7 × 6) ÷ (1 × 2 × 3) = 56 options, choice B. And when the pizza place has nine toppings, Sam has (9 × 8 × 7) ÷ (1 × 2 × 3) = 84 options, choice D.
Correction in calculation it should be 56 instead of 42 and hence the option will be C
