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Kate and Chad are planning their wedding dinner and must sel
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30 Dec 2017, 14:28
30 Dec 2017, 14:28
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Question Stats:
87% (00:58) correct
12% (00:47) wrong based on 58 sessions
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Kate and Chad are planning their wedding dinner and must select 3 of 12 entrees and 2 of 3 desserts for their guests to be able to choose from. How many different combinations of
offerings are possible?
offerings are possible?
Drill 2
Question: 6
Page: 563
Question: 6
Page: 563
Show: :: OA
660
Re: Kate and Chad are planning their wedding dinner and must sel
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08 Jan 2018, 16:31
08 Jan 2018, 16:31
Expert Reply
Explanation
The order of entrees the guests chose from does not matter.
Therefore, the number of different possibilities of entrees is \(\frac{12 \times 11 \times 10}{3 \times 2 \times 1}\)=220. The order of desserts does not matter
either, so there are \(\frac{3 \times 2}{2}\)=3 possible different combinations of desserts.
Multiplying the two together gives a total of 660 possible different combinations of offerings.
The order of entrees the guests chose from does not matter.
Therefore, the number of different possibilities of entrees is \(\frac{12 \times 11 \times 10}{3 \times 2 \times 1}\)=220. The order of desserts does not matter
either, so there are \(\frac{3 \times 2}{2}\)=3 possible different combinations of desserts.
Multiplying the two together gives a total of 660 possible different combinations of offerings.
Re: Kate and Chad are planning their wedding dinner and must sel
[#permalink]
23 Jan 2018, 11:17
23 Jan 2018, 11:17
1
12C3 * 3C2
660
660
