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In circle P, the two chords intersect at point X, with the l
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08 Jan 2018, 15:05
08 Jan 2018, 15:05
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45% (01:08) correct
54% (01:52) wrong based on 42 sessions
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#GREpracticequestion In circle P, the two chords intersect at point X.jpg [ 14.2 KiB | Viewed 5519 times ]
In circle P, the two chords intersect at point X, with the lengths as indicated in the figure. Which could NOT be the sum of the lengths a and b , if a and b are integers?
A. 30
B. 26
C. 19
D. 16
E. 14
Kudo for the right answer and explanation.
Re: In circle P, the two chords intersect at point X, with the l
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10 Jan 2018, 01:27
10 Jan 2018, 01:27
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1
So according to me ( I am pretty bad at geometry) is to draw line between AD and BC and you will see two triangles that is similar triangles.
So AX/XB = DX/XC
We know that AX = 6 and XB = 8
So the ratio is 3/4 so it must follows that DX/XC must have the same !
So C.
Anyone has a better explanation?
So AX/XB = DX/XC
We know that AX = 6 and XB = 8
So the ratio is 3/4 so it must follows that DX/XC must have the same !
So C.
Anyone has a better explanation?
Re: In circle P, the two chords intersect at point X, with the l
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10 Jan 2018, 01:53
10 Jan 2018, 01:53
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Quote:
When two chords intersect within a circle, the product of the segments on one chord is equal to the product of the segments on the other chord. Because the segments of the first chord are 6 and 8, the product of the lengths is 48. Thus, the product of the lengths a and b must be 48. Possible lengths are 48 and 1, 24 and 2, 16 and 3, 12 and 4, and 8 and 6, so possible values for a + b are 49, 26, 19, i6, and 14. The correct answer is choice A because 3o is not the sum of two integer factors of 48.
