Last visit was: 13 Nov 2024, 22:32 It is currently 13 Nov 2024, 22:32

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
Verbal Expert
Joined: 18 Apr 2015
Posts: 29955
Own Kudos [?]: 36213 [0]
Given Kudos: 25903
Send PM
avatar
Manager
Manager
Joined: 25 Nov 2017
Posts: 51
Own Kudos [?]: 67 [0]
Given Kudos: 0
Send PM
avatar
Retired Moderator
Joined: 20 Apr 2016
Posts: 1307
Own Kudos [?]: 2273 [0]
Given Kudos: 251
WE:Engineering (Energy and Utilities)
Send PM
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 12188 [0]
Given Kudos: 136
Send PM
Re: |2y -5|<1 [#permalink]
3
Carcass wrote:
\(|2y -5|<1\)

Quantity A
Quantity B
y
1




When solving inequalities involving ABSOLUTE VALUE, there are 2 things you need to know:
Rule #1: If |something| < k, then –k < something < k
Rule #2: If |something| > k, then EITHER something > k OR something < -k
Note: these rules assume that k is positive


Given: |2y - 5| < 1
So, by Rule #1, we get: -1 < 2y - 5 < 1
Add 5 to all sides to get: 4 < 2y < 6
Divide all sides by 2 to get: 2 < y < 3

Since y is between 2 and 3, y MUST be greater than 1

Answer: A

Cheers,
Brent
avatar
Intern
Intern
Joined: 07 Oct 2017
Posts: 30
Own Kudos [?]: 6 [0]
Given Kudos: 0
Send PM
Re: |2y -5|<1 [#permalink]
Could you suggest the tougher inequalities and absolute problems for practice?
I take the GRE in 2 weeks and I keep getting problems in absolute/inequalities wrong.
Verbal Expert
Joined: 18 Apr 2015
Posts: 29955
Own Kudos [?]: 36213 [0]
Given Kudos: 25903
Send PM
Re: |2y -5|<1 [#permalink]
Expert Reply
Just click on the tag above the question "absolute value" and you do have all the questions present on the board

Here https://gre.myprepclub.com/forum/search.ph ... tag_id=234

Also. here on the correct usage of the tags https://gre.myprepclub.com/forum/using-tag ... tml#p15585

Regards
avatar
Intern
Intern
Joined: 07 Feb 2018
Posts: 13
Own Kudos [?]: 2 [0]
Given Kudos: 0
Send PM
Re: |2y -5|<1 [#permalink]
Answer: A
avatar
Intern
Intern
Joined: 11 Jan 2018
Posts: 44
Own Kudos [?]: 104 [0]
Given Kudos: 0
Send PM
Re: |2y -5|<1 [#permalink]
pranab01 wrote:
Carcass wrote:
\(|2y -5|<1\)

Quantity A
Quantity B
y
1


A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal
D. The relationship cannot be determined from the information given.

kudo for the right solution and explanation



Here we have to consider negative and positive value of |2y -5|.

Considering (2y - 5) to be negative

or -(2y - 5) < 1

or 2y - 5 > -1 (equality changes as the sign changes)

or 2y > 4 (adding 5 on both side)

or y > 2

Now consider positive

|2y -5|<1

or 2y - 5 < 1

or 2y < 6 (adding 5 on both side)

or y <3

Therefore the value of y is = 2 < y < 3

Hence statement A.


I used same method, and yes that's correct answer. Choice A
avatar
Intern
Intern
Joined: 17 Feb 2018
Posts: 9
Own Kudos [?]: 2 [0]
Given Kudos: 0
Send PM
Re: |2y -5|<1 [#permalink]
GreenlightTestPrep wrote:
Carcass wrote:
\(|2y -5|<1\)

Quantity A
Quantity B
y
1




When solving inequalities involving ABSOLUTE VALUE, there are 2 things you need to know:
Rule #1: If |something| < k, then –k < something < k
Rule #2: If |something| > k, then EITHER something > k OR something < -k
Note: these rules assume that k is positive


Given: |2y - 5| < 1
So, by Rule #1, we get: -1 < 2y - 5 < 1
Add 5 to all sides to get: 4 < 2y < 6
Divide all sides by 2 to get: 2 < y < 3

Since y is between 2 and 3, y MUST be greater than 1

Answer: A

Cheers,
Brent


thanks for the insight
Prep Club for GRE Bot
Re: |2y -5|<1 [#permalink]
Moderators:
GRE Instructor
78 posts
GRE Forum Moderator
37 posts
Moderator
1111 posts
GRE Instructor
234 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne