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If b/a+b
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08 Jan 2018, 14:27
08 Jan 2018, 14:27
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If \(\frac{b}{a+b} = \frac{7}{12}\), then what does \(\frac{a}{b}\) equal ?
A. \(\frac{7}{19}\)
B. \(\frac{5}{12}\)
C. \(\frac{5}{7}\)
D. \(\frac{7}{5}\)
E. \(\frac{19}{12}\)
A. \(\frac{7}{19}\)
B. \(\frac{5}{12}\)
C. \(\frac{5}{7}\)
D. \(\frac{7}{5}\)
E. \(\frac{19}{12}\)
Re: If b/a+b
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10 Jan 2018, 01:21
10 Jan 2018, 01:21
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Lets develop
7(a+b) = 12 b
7 a + 7b = 12b
7a = 5b
7a/b = 5
A/b = 5/7
So answer C
7(a+b) = 12 b
7 a + 7b = 12b
7a = 5b
7a/b = 5
A/b = 5/7
So answer C
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If b/a+b
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10 Jan 2018, 10:47
10 Jan 2018, 10:47
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Carcass wrote:
If \(\frac{b}{a+b} = \frac{7}{12}\), then what does \(\frac{a}{b}\) equal ?
A. \(\frac{7}{19}\)
B. \(\frac{5}{12}\)
C. \(\frac{5}{7}\)
D. \(\frac{7}{5}\)
E. \(\frac{19}{12}\)
A. \(\frac{7}{19}\)
B. \(\frac{5}{12}\)
C. \(\frac{5}{7}\)
D. \(\frac{7}{5}\)
E. \(\frac{19}{12}\)
Here's another approach that uses a often-tested property: (x + y)/z = x/z + y/z
If b/(a+b) = 7/12, then we can also say that (a + b)/b = 12/7
Applying the above property, we can write: a/b + b/b = 12/7
Simplify: a/b + 1 = 12/7
Subtract 1 from both sides to get: a/b = 12/7 - 1
Rewrite 1 as follows: a/b = 12/7 - 7/7
Evaluate: a/b = 5/7
Answer: C
