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Paul and Allen are choosing ties out of a selection of three
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30 Dec 2017, 14:31
30 Dec 2017, 14:31
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Question Stats:
53% (01:06) correct
46% (01:33) wrong based on 47 sessions
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Paul and Allen are choosing ties out of a selection of three distinct red ties, five distinct green ties, and six distinct blue ties. If Paul and Allen each wear one tie, how many different ways could they wear ties of the same color?
Drill 2
Question: 14
Page: 565
Question: 14
Page: 565
Show: :: OA
56
Re: Paul and Allen are choosing ties out of a selection of three
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12 Jan 2018, 15:37
12 Jan 2018, 15:37
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Explanation
This problem involves permutations, because the order matters since the ties are all distinct. Start with Paul wearing a red tie. He has 3 red tie choices and Allen has 2 remaining red tie choices, giving them a product of 6 permutations.
For green ties, they have 5 × 4 = 20 permutations. For blue ties, they have 6 × 5 = 30 permutations. The grand total is 56 permutations.
This problem involves permutations, because the order matters since the ties are all distinct. Start with Paul wearing a red tie. He has 3 red tie choices and Allen has 2 remaining red tie choices, giving them a product of 6 permutations.
For green ties, they have 5 × 4 = 20 permutations. For blue ties, they have 6 × 5 = 30 permutations. The grand total is 56 permutations.
Re: Paul and Allen are choosing ties out of a selection of three
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08 Aug 2022, 08:03
08 Aug 2022, 08:03
1
The possibilities are R and R or B and B or G and G = 3*2 + 6*5 + 5*4 = 56
