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(3y+2)/5
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30 Sep 2015, 14:58
30 Sep 2015, 14:58
1
00:00
Question Stats:
42% (00:28) correct
57% (00:29) wrong based on 21 sessions
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Quantity A |
Quantity B |
\(\frac{(3y+2)}{5}\) |
\(y\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
As I know , one approach to solve that is by simplifying the Quantity A , And to simplify it , First I will multiply the denominator , but I am not sure , Do I need to multiply both denominator and the numerator by the same value (5) so the new numerator will be after multiplying (5y+10) or just I cancel off the denominator by removing (5) without any changes in the numerator , I feel like 5 is must be multiply be the whole fraction (numerator and denominator but I see some answers there was no effect on the denominator when trying to cancel off the denominator ?
Also, everything I do in quantity comparison question to one Quantity i must then do the same to the other , is that correct even there is no equal relation for both quantity ?
Re: Getting rid of the denominator
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02 Oct 2015, 08:58
02 Oct 2015, 08:58
Expert Reply
Here we have
\(\frac{(3Y + 2)}{5}\) ............. Y
\(0.6Y + 0.4\) .............. Y
\(0.4\) .............. 0.4 Y
\(1\) .............. Y
Y may be greater or less than 1
Hence cannot be determined
\(\frac{(3Y + 2)}{5}\) ............. Y
\(0.6Y + 0.4\) .............. Y
\(0.4\) .............. 0.4 Y
\(1\) .............. Y
Y may be greater or less than 1
Hence cannot be determined
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Re: Getting rid of the denominator - (3Y+2)/5
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05 Oct 2015, 11:30
05 Oct 2015, 11:30
1
jaber wrote:
Quantity A: (3Y+2)/5
Quantity B: Y
Multiply both quantities by 5 to get:
Quantity A: 3Y+2
Quantity B: 5Y
Subtract 3Y from both quantities:
Quantity A: 2
Quantity B: 2Y
At this point we can see the answer, but let's do one more step for "fun"
Divide both quantities by 2:
Quantity A: 1
Quantity B: Y
No way to tell which is greater. Answer: D
For more on the strategy of performing the same operation to both quantities, see this free video - http://www.greenlighttestprep.com/modul ... video/1097
