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Re: P and Q are roots [#permalink]
Answer: A
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Re: P and Q are roots [#permalink]
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Carcass wrote:

P and Q are roots of \(x^2 - 9x = 36\)

Quantity A
Quantity B
\(P+Q\)
\(P*Q\)



A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Kudos for the right solution and explanation


In the quadratic equation; \(ax^2 + bx + c\)
Sum of the roots = \(\frac{-b}{a}\)
Product of the roots = \(\frac{c}{a}\)

Now, \(x^2 - 9x - 36 = 0\)

Col. A: \(\frac{-(-9)}{1} = 9\)
Col. B: \(\frac{(-9)}{1} = -36\)

Hence, option A
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P and Q are roots [#permalink]
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Always need to remember this formula for time saving!

In the quadratic equation; \(ax^2+bx+c = 0\)
Sum of the roots = \(\frac{-b}{a}\)
Product of the roots = \(\frac{c}{a}\)
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P and Q are roots [#permalink]
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