GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
r > zero
[#permalink]
04 Feb 2018, 15:07
04 Feb 2018, 15:07
Expert Reply
00:00
Question Stats:
93% (00:28) correct
6% (00:28) wrong based on 83 sessions
Hide Show timer Statistics
\(r > 0\)
Quantity A |
Quantity B |
\(\frac{7}{r+8}\) |
\(\frac{7}{r}\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Kudos for the right solution and explanation
Sherpa Prep Representative
Joined: 15 Jan 2018
Posts: 147
Given Kudos: 0
Re: r > zero
[#permalink]
Updated on: 08 Feb 2018, 08:43
Updated on: 08 Feb 2018, 08:43
3
Expert Reply
The easiest way to solve this one is to cross-multiply and then subtract the common values. We're allowed to do this, btw, because we've been told r is positive. If we hadn't been told anything about whether r is positive or negative, we wouldn't be able to use this technique. See attached picture. Since the simplest version of this problem is 0 vs 56, we can see that Quantity B is bigger.
Attachments
IMG_20180208_113654.jpg [ 39.25 KiB | Viewed 6733 times ]
Originally posted by SherpaPrep on 04 Feb 2018, 20:32.
Last edited by SherpaPrep on 08 Feb 2018, 08:43, edited 2 times in total.
Last edited by SherpaPrep on 08 Feb 2018, 08:43, edited 2 times in total.
Re: r > zero
[#permalink]
05 Feb 2018, 02:37
05 Feb 2018, 02:37
1
Carcass wrote:
\(r > 0\)
Quantity A |
Quantity B |
\(\frac{7}{r+8}\) |
\(\frac{7}{r}\) |
Here given r>0
So the value of r has to be positive. It can be either integer or a fraction.
Now we know if denominator > numerator then the value will be always less than 1.
Now compare QTY A and QTY b,
we can see that QTY A has denominator r+8, and the denominator of QTY B is r, so what ever the value of r (i.e integer or fraction) the value of QTY B > QTY A
