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The average(arithmetic mean) of 50 measurements is 34.6
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Updated on: 05 Feb 2018, 01:52
Updated on: 05 Feb 2018, 01:52
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Question Stats:
69% (00:58) correct
30% (01:19) wrong based on 39 sessions
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The average(arithmetic mean) of 50 measurements is 34.6, and the least and the greatest of the measurements are 18.3 and 51.7 respectively.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The median of the 50 measurements |
34.6 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: statistics problem
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26 Jan 2018, 06:43
26 Jan 2018, 06:43
1
Expert Reply
Please follow the rules how to post in the right way a question here https://gre.myprepclub.com/forum/qq-how-to ... -2357.html and the rules for posting o the board here https://gre.myprepclub.com/forum/rules-for ... -1083.html
Thank you in advance
Thank you in advance
Re: statistics problem
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04 Feb 2018, 16:28
04 Feb 2018, 16:28
1
D
we know the sum must be 34.6*50=1730
Try to prove theyre equal first then prove they are not equal to prove D.
1th 2-24 25 & 26 27-49 50th
18.3 34.6 34.6 51.7
to make the median 34.6 the 25th and 26th term's avg must be 34.6, the easiest case is 34.6 34.6
if you fill the rest with numbers less than 51.7 for 27-49 but greater or equal than 34.6 and the 2-24th term with numbers less than 34.6 , the sum can exceed 1730 and also make it equal
now try to check if you can get the same sum (1730) with differrent terms for the 25 and 26th slots.
then try to fill in the rest to make the sum 1730 or larger
18.3 33.6 34.6 51.7
if you choose about the same numbers as the first case you will get a sum larger or equal to 1730 but with a different median.
D
sorry i couldnt come up with a better solution there probably is.
we know the sum must be 34.6*50=1730
Try to prove theyre equal first then prove they are not equal to prove D.
1th 2-24 25 & 26 27-49 50th
18.3 34.6 34.6 51.7
to make the median 34.6 the 25th and 26th term's avg must be 34.6, the easiest case is 34.6 34.6
if you fill the rest with numbers less than 51.7 for 27-49 but greater or equal than 34.6 and the 2-24th term with numbers less than 34.6 , the sum can exceed 1730 and also make it equal
now try to check if you can get the same sum (1730) with differrent terms for the 25 and 26th slots.
then try to fill in the rest to make the sum 1730 or larger
18.3 33.6 34.6 51.7
if you choose about the same numbers as the first case you will get a sum larger or equal to 1730 but with a different median.
D
sorry i couldnt come up with a better solution there probably is.
